(D) The efficiency $\eta$ of a Carnot engine is given by $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ and $T_2$ are the absolute temperatures in Kelvin.Gi

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(D) The efficiency $\eta$ of a Carnot engine is given by $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ and $T_2$ are the absolute temperatures in Kelvin.Given $T_1 = 227^{\circ}C = 227 + 273 = 500 \, K$ and $T_2 = 127^{\circ}C = 127 + 273 = 400 \, K$.$\eta = 1 - \frac{400}{500} = 1 - 0.8 = 0.2$ or $\frac{1}{5}$.Since efficiency $\eta = \frac{W}{Q_1}$,where $W$ is the work done and $Q_1$ is the heat absorbed at high temperature:$W = \eta \times Q_1 = \frac{1}{5} \times (6 \times 10^4 \, J) = 1.2 \times 10^4 \, J$.

Class 11 Physics Thermodynamics Heat Engine and Carnot Cycle

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An ideal gas heat engine operates in a Carnot cycle between $227^{\circ}C$ and $127^{\circ}C$. It absorbs $6 \times 10^4 \, J$ of heat at the high temperature. The amount of heat converted into work is:

A
$4.8 \times 10^4 \, J$
B
$3.5 \times 10^4 \, J$
C
$1.6 \times 10^4 \, J$
D
$1.2 \times 10^4 \, J$

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Heat Engine and Carnot Cycle

$A$ Carnot engine whose efficiency is $40 \%$,receives heat at $500 \ K$. If the efficiency is to be $50 \%$,the source temperature for the same exhaust temperature is (in $K$)

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Explain: Carnot cycle and Carnot engine.

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Three Carnot engines operate in series between a heat source at a temperature $T_1$ and a heat sink at temperature $T_4$ (see figure). There are two other reservoirs at temperatures $T_2$ and $T_3$,as shown,with $T_1 > T_2 > T_3 > T_4$. The three engines are equally efficient if

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In a Carnot engine,the temperature of the reservoir is $927\ ^oC$ and that of the sink is $27\ ^oC.$ If the work done by the engine is $12.6 \times 10^6 \ J,$ the quantity of heat absorbed by the engine from the reservoir is:

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$A$ reversible Carnot heat engine converts $\frac{1}{4}$ of its input heat into work. When the temperature of the sink is reduced by $50 \ K$,its efficiency becomes $33 \frac{1}{3} \%$. The initial temperatures of the source and the sink respectively are

MediumAP EAMCET 2018

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An ideal gas heat engine operates in a Carnot cycle between $227^{\circ}C$ and $127^{\circ}C$. It absorbs $6 \times 10^4 \, J$ of heat at the high temperature. The amount of heat converted into work is:

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$A$ Carnot engine whose efficiency is $40 \%$,receives heat at $500 \ K$. If the efficiency is to be $50 \%$,the source temperature for the same exhaust temperature is (in $K$)

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