An ideal gas expands isothermally from 10^{-3 | vedclass

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(B) The work done on the gas during an expansion against a constant external pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$Given:$P_

Vedclass · Accepted Answer

$-900 \; J$

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(B) The work done on the gas during an expansion against a constant external pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$Given:$P_{ext} = 10^{5} \; Nm^{-2}$$V_i = 10^{-3} \; m^{3}$$V_f = 10^{-2} \; m^{3}$Change in volume $\Delta V = V_f - V_i = 10^{-2} - 10^{-3} = 10^{-2} - 0.1 	imes 10^{-2} = 0.9 	imes 10^{-2} \; m^{3}$Substituting the values:$W = -10^{5} \; Nm^{-2} 	imes (0.9 	imes 10^{-2} \; m^{3})$$W = -0.9 	imes 10^{3} \; J$$W = -900 \; J$Since the work done is negative,it indicates that work is done by the gas on the surroundings.

An ideal gas expands isothermally from $10^{-3} \; m^{3}$ to $10^{-2} \; m^{3}$ at $300 \; K$ against a constant external pressure of $10^{5} \; Nm^{-2}$. The work done on the gas is:

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