An element has BCC structure with edge length | vedclass

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Question

(A) For a $BCC$ (Body-Centered Cubic) structure, the relationship between the edge length $(a)$ and the atomic radius $(r)$ is given by the formula: $

Vedclass · Accepted Answer

$\sqrt{3} 	imes 150 \ pm$

Vedclass · Answer

(A) For a $BCC$ (Body-Centered Cubic) structure, the relationship between the edge length $(a)$ and the atomic radius $(r)$ is given by the formula: $\sqrt{3} a = 4 r$. Given that the edge length $a = 600 \ pm$. Substituting the value of $a$ into the formula: $r = \frac{\sqrt{3} a}{4} = \frac{\sqrt{3} 	imes 600}{4}$. Calculating the value: $r = \sqrt{3} 	imes 150 \ pm$.

An element has $BCC$ structure with edge length of unit cell $600 \ pm$. What is the atomic radius of the element?

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