An electron with energy $0.1 \, keV$ moves at a right angle to the Earth's magnetic field of $1 \times 10^{-4} \, Wb/m^2$. The frequency of revolution of the electron will be. (Take mass of electron $= 9.0 \times 10^{-31} \, kg$)
- A$1.6 \times 10^5 \, Hz$
- B$5.6 \times 10^5 \, Hz$
- C$2.8 \times 10^6 \, Hz$
- D$1.8 \times 10^6 \, Hz$
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