(B) When an electron is accelerated through a potential difference $V$,its kinetic energy is given by $K = eV$. Since the kinetic energy is $K = \frac

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(B) When an electron is accelerated through a potential difference $V$,its kinetic energy is given by $K = eV$. Since the kinetic energy is $K = \frac{1}{2}mv^2$,we have: $\frac{1}{2}mv^2 = eV$ Rearranging for $V$: $V = \frac{mv^2}{2e}$ Substituting the given values: $m = 9 \times 10^{-31} \ kg$,$v = 1.6 \times 10^7 \ m/s$,$e = 1.6 \times 10^{-19} \ C$ $V = \frac{(9 \times 10^{-31}) \times (1.6 \times 10^7)^2}{2 \times 1.6 \times 10^{-19}}$ $V = \frac{9 \times 10^{-31} \times 2.56 \times 10^{14}}{3.2 \times 10^{-19}}$ $V = \frac{23.04 \times 10^{-17}}{3.2 \times 10^{-19}}$ $V = 7.2 \times 10^2 \ V$

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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An electron moving with velocity $1.6 \times 10^7 \ m/s$ has a wavelength of $0.4 \ \mathring{A}$. The required accelerating voltage for the electron motion is (charge on electron $= 1.6 \times 10^{-19} \ C$,mass of electron $= 9 \times 10^{-31} \ kg$).

MHT CET 2023 All MHT CET

A
$7.2 \times 10^3 \ V$
B
$7.2 \times 10^2 \ V$
C
$7.2 \ \text{V}$
D
$7.2 \times 10^{-2} \ V$

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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An electron moving with velocity $1.6 \times 10^7 \ m/s$ has a wavelength of $0.4 \ \mathring{A}$. The required accelerating voltage for the electron motion is (charge on electron $= 1.6 \times 10^{-19} \ C$,mass of electron $= 9 \times 10^{-31} \ kg$).

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For photoelectric emission from a certain metal,the cutoff frequency is $\nu$. If radiation of frequency $2\nu$ impinges on the metal plate,the maximum possible velocity of the emitted electron will be ($m$ is the electron mass).

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