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Question

(c) If the voltage given is $V$, then the energy of electron
$\frac{1}{2}m{v^2} = eV$

$\Rightarrow v = \sqrt {\frac{{2eV}}{m}} $

$ = \sqrt {\fr

Vedclass · Accepted Answer

$1.9 	imes {10^7}m/s$

Vedclass · Answer

(c) If the voltage given is $V$, then the energy of electron
$\frac{1}{2}m{v^2} = eV$

$\Rightarrow v = \sqrt {\frac{{2eV}}{m}} $

$ = \sqrt {\frac{{2 	imes 1.6 	imes {{10}^{ - 19}} 	imes 1000}}{{9.1 	imes {{10}^{ - 31}}}}} = 1.875 	imes {10^7}$$ \approx 1.9 	imes {10^7}m/s$

An electron is accelerated through a potential difference of $1000$ volts. Its velocity is nearly

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