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(D) When a charged particle with charge $q$ and mass $m$ enters a uniform magnetic field $B$ with velocity $v$ perpendicular to the field,it experienc

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in a circular path with a radius directly proportional to its velocity

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(D) When a charged particle with charge $q$ and mass $m$ enters a uniform magnetic field $B$ with velocity $v$ perpendicular to the field,it experiences a magnetic Lorentz force $F = q(v 	imes B)$.Since the force is always perpendicular to the velocity,it acts as a centripetal force,causing the particle to move in a circular path.The radius $r$ of this circular path is given by the formula:$r = \frac{mv}{qB}$From this expression,it is clear that the radius $r$ is directly proportional to the velocity $v$ $(r \propto v)$.Therefore,the particle travels in a circular path with a radius directly proportional to its velocity.

An electrically charged particle enters a uniform magnetic field in a direction perpendicular to the field with a velocity $v$. Then,it travels:

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