An electric potential difference will be indu | vedclass

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Question

(D) The motional electromotive force $(EMF)$ induced in a conductor moving in a magnetic field is given by the formula $\varepsilon = B l v \sin 	het

Vedclass · Accepted Answer

$M$

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(D) The motional electromotive force $(EMF)$ induced in a conductor moving in a magnetic field is given by the formula $\varepsilon = B l v \sin 	heta$,where $B$ is the magnetic field,$l$ is the length of the conductor,$v$ is the velocity,and $	heta$ is the angle between the velocity vector and the magnetic field lines.For an $EMF$ to be induced,the conductor must cut the magnetic field lines. In the given diagram,the magnetic field lines are directed from the North $(N)$ pole to the South $(S)$ pole (horizontally).If the conductor moves in the direction $L$ or $Q$,it moves parallel to the magnetic field lines,so $	heta = 0^\circ$ or $180^\circ$,and $\sin 	heta = 0$,resulting in no induced $EMF$.If the conductor moves in the direction $P$,it moves parallel to its own length,which does not cut the magnetic field lines effectively to induce a potential difference across its ends.If the conductor moves in the direction $M$ (perpendicular to the magnetic field lines),it cuts the magnetic field lines,resulting in the induction of an electric potential difference between its ends. Therefore,the correct direction is $M$.

An electric potential difference will be induced between the ends of the conductor shown in the diagram,when the conductor moves in the direction

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