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(D) The current $I$ enters at one point and leaves at the diametrically opposite point of the circular wire. This divides the wire into two semicircul

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(D) The current $I$ enters at one point and leaves at the diametrically opposite point of the circular wire. This divides the wire into two semicircular arcs,each carrying a current of $I/2$.For each semicircular arc,the magnetic field produced at the center of the circle can be calculated using the Biot-Savart law. The magnetic field due to a semicircular arc at its center is $B = \frac{\mu_{0} I_{arc}}{4r}$.Since the two semicircular arcs carry current in opposite directions relative to the center,the magnetic fields produced by them at the center are equal in magnitude but opposite in direction.Specifically,if one arc produces a magnetic field $B$ pointing into the page,the other arc produces a magnetic field $B$ pointing out of the page.Therefore,the net magnetic field $B_{net}$ at the center of the circle is $B - B = 0$.The magnetic force $F$ on a charge $q$ moving with velocity $v$ in a magnetic field $B$ is given by $F = q(v 	imes B)$.Since the net magnetic field $B_{net}$ at the center is $0$,the magnetic force experienced by the particle is $F = q(v 	imes 0) = 0$.

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