An earth satellite $S$ has an orbit radius which is $4$ times that of a communication satellite $C$. The period of revolution of $S$ is ........ $days$
An earth satellite $S$ has an orbit radius which is $4$ times that of a communication satellite $C$. The period of revolution of $S$ is ........ $days$
- A
$4$
- B
$8$
- C
$16$
- D
$32$
Similar Questions
When a satellite moves around the earth in a certain orbit, the quantity which remains constant is :
When a satellite moves around the earth in a certain orbit, the quantity which remains constant is :
Two satellites are launched at a distance $R$ from a planet of negligible radius. Both satellites are launched in the tangential direction. The first satellite launches correctly at a speed $v_0$ and enters a circular orbit. The second satellite, however, is launched at a speed $\frac {1}{2}v_0$ . What is the minimum distance between the second satellite and the planet over the course of its orbit?
Two satellites are launched at a distance $R$ from a planet of negligible radius. Both satellites are launched in the tangential direction. The first satellite launches correctly at a speed $v_0$ and enters a circular orbit. The second satellite, however, is launched at a speed $\frac {1}{2}v_0$ . What is the minimum distance between the second satellite and the planet over the course of its orbit?
Kepler discovered
Kepler discovered
The largest and the shortest distance of the earth from the sun are ${r_1}$ and ${r_2}$, its distance from the sun when it is at the perpendicular to the major axis of the orbit drawn from the sun
The largest and the shortest distance of the earth from the sun are ${r_1}$ and ${r_2}$, its distance from the sun when it is at the perpendicular to the major axis of the orbit drawn from the sun
- [AIPMT 1988]
Write the Kepler law of period (Kepler’s third law) for planetary motion.
Write the Kepler law of period (Kepler’s third law) for planetary motion.