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(B) Power $P = 300 \, MW = 300 	imes 10^6 \, J/s$.Energy released per fission $E = 170 \, MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19} \, J = 2.7

Vedclass · Accepted Answer

$4 	imes 10^{22}$

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(B) Power $P = 300 \, MW = 300 	imes 10^6 \, J/s$.Energy released per fission $E = 170 \, MeV = 170 	imes 10^6 	imes 1.6 	imes 10^{-19} \, J = 2.72 	imes 10^{-11} \, J$.The power output is given by $P = \frac{n E}{t}$, where $n$ is the number of atoms fissioned in time $t$.For $t = 1 \, s$, the number of atoms fissioned per second is $n_s = \frac{P}{E} = \frac{300 	imes 10^6}{2.72 	imes 10^{-11}} \approx 1.103 	imes 10^{19} \, 	ext{atoms/s}$.Number of atoms fissioned per hour $(3600 \, s)$ is $N = n_s 	imes 3600 = 1.103 	imes 10^{19} 	imes 3600 \approx 3.97 	imes 10^{22} \approx 4 	imes 10^{22}$ atoms.

An atomic power nuclear reactor can deliver $300 \, MW$. The energy released due to the fission of each nucleus of a uranium atom $U^{238}$ is $170 \, MeV$. The number of uranium atoms fissioned per hour will be:

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