An atomic nucleus having a low n/p ratio trie | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Nuclei with a low $n/p$ ratio are proton-rich and unstable. They achieve stability by increasing the $n/p$ ratio. This can occur through two prima

Vedclass · Accepted Answer

the emission of a positron

Vedclass · Answer

(B) Nuclei with a low $n/p$ ratio are proton-rich and unstable. They achieve stability by increasing the $n/p$ ratio. This can occur through two primary processes: $1$. Positron emission: $^1_1p ightarrow ^1_0n + ^0_{+1}e + 
u$ $2$. $K$-electron capture: $^1_1p + ^0_{-1}e ightarrow ^1_0n + 
u$ Both processes convert a proton into a neutron,thereby decreasing the number of protons and increasing the number of neutrons,which increases the $n/p$ ratio. Since both options $(B)$ and $(C)$ are correct,in many contexts,positron emission is the primary answer provided for this specific question type.

An atomic nucleus having a low $n/p$ ratio tries to find stability by:

Similar Questions

Hydrogen can be fused to form helium at

Ordinary water is not used as a moderator in nuclear reactors because

The end product of the $(4n + 2)$ radioactive disintegration series is:

Calculate the mass defect in the following nuclear reaction:
$_1H^2 + _1H^3 \to _2He^4 + _0n^1$
(Given: mass of $_1H^2 = 2.014 \ amu$,$_1H^3 = 3.016 \ amu$,$_2He^4 = 4.004 \ amu$,$_0n^1 = 1.008 \ amu$) (in $amu$)

Starting from radium,the radioactive disintegration process terminates when the following is obtained:

Vedclass Test Series

Exam Paper Generator

Online Exam Module