The end product of the $(4n + 2)$ radioactive disintegration series is:

  • A
    $_{82}Pb^{208}$
  • B
    $_{82}Pb^{206}$
  • C
    $_{82}Pb^{207}$
  • D
    $_{83}Bi^{210}$

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Similar Questions

In a nuclear reactor,the chain reaction is controlled by introducing:

Let $m_p$ be the mass of a proton,$m_n$ that of a neutron,$M_1$ that of a $_{10}^{20}Ne$ nucleus,and $M_2$ that of a $_{20}^{40}Ca$ nucleus. Then:

$_{90}Th^{228}$ emits four alpha and one beta particles. The number of neutrons in the daughter element is:

Large energy released in an atomic bomb explosion is mainly due to

${}_{90}Th^{232} \rightarrow {}_{82}Pb^{208}$. The number of $\alpha$ and $\beta$-particles emitted during the above reaction is:

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