(B) The instantaneous power in an $AC$ circuit is given by $P = V_{rms} I_{rms} \cos \phi$, where $\phi$ is the phase difference between voltage and c

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The instantaneous power in an $AC$ circuit is given by $P = V_{rms} I_{rms} \cos \phi$, where $\phi$ is the phase difference between voltage and current.Given voltage $V = V_{0} \sin \omega t$ and current $I = I_{0} \sin (\omega t - \frac{\pi}{2})$.The phase difference $\phi = \frac{\pi}{2}$.The power consumed is $P = V_{rms} I_{rms} \cos \phi = \frac{V_{0}}{\sqrt{2}} \cdot \frac{I_{0}}{\sqrt{2}} \cdot \cos(\frac{\pi}{2})$.Since $\cos(\frac{\pi}{2}) = 0$, the power consumed $P = 0$ watt.

Class 12 Physics Alternating Current Power in AC and Power Factor

Easy

An alternating voltage of $V = V_{0} \sin \omega t$ is applied across a circuit. As a result, a current $I = I_{0} \sin (\omega t - \frac{\pi}{2})$ flows in it. The power consumed per cycle is . . . . . . .

GUJCET 2006 All GUJCET

A
$1.919 V_{0} I_{0}$ watt
B
$0$ watt
C
$0.5 V_{0} I_{0}$ watt
D
$0.707 V_{0} I_{0}$ watt

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Alternating Current

Subtopic

Power in AC and Power Factor

Previous Year

GUJCET 2006 Paper All GUJCET years →

$(a)$ For circuits used for transporting electric power, a low power factor implies large power loss in transmission. Explain.
$(b)$ Power factor can often be improved by the use of a capacitor of appropriate capacitance in the circuit. Explain.

Difficult

View Solution

In an $AC$ circuit,$V$ and $I$ are given below. Find the power dissipated in the circuit:
$V = 50 \sin(50t) \ V$
$I = 50 \sin(50t + \frac{\pi}{3}) \ mA$ (in $W$)

EasyAP EAMCET 2015

View Solution

Power dissipated in an $LCR$ series circuit connected to an $A.C.$ source of $e.m.f.$ $\varepsilon$ is

MediumAIPMT 2009

View Solution

In a series $LCR$ circuit,an alternating emf $(v)$ and current $(i)$ are given by the equations $v = v_{0} \sin \omega t$ and $i = i_{0} \sin \left(\omega t + \frac{\pi}{3}\right)$. The average power dissipated in the circuit over a cycle of $AC$ is:

MediumKCET 2016

View Solution

From which of the following options can the power factor of an $AC$ circuit be zero?

EasyGSEB 2024

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

An alternating voltage of $V = V_{0} \sin \omega t$ is applied across a circuit. As a result, a current $I = I_{0} \sin (\omega t - \frac{\pi}{2})$ flows in it. The power consumed per cycle is . . . . . . .

Similar Questions

$(a)$ For circuits used for transporting electric power, a low power factor implies large power loss in transmission. Explain.$(b)$ Power factor can often be improved by the use of a capacitor of appropriate capacitance in the circuit. Explain.

In an $AC$ circuit,$V$ and $I$ are given below. Find the power dissipated in the circuit: $V = 50 \sin(50t) \ V$ $I = 50 \sin(50t + \frac{\pi}{3}) \ mA$ (in $W$)

Power dissipated in an $LCR$ series circuit connected to an $A.C.$ source of $e.m.f.$ $\varepsilon$ is

In a series $LCR$ circuit,an alternating emf $(v)$ and current $(i)$ are given by the equations $v = v_{0} \sin \omega t$ and $i = i_{0} \sin \left(\omega t + \frac{\pi}{3}\right)$. The average power dissipated in the circuit over a cycle of $AC$ is:

From which of the following options can the power factor of an $AC$ circuit be zero?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$(a)$ For circuits used for transporting electric power, a low power factor implies large power loss in transmission. Explain.
$(b)$ Power factor can often be improved by the use of a capacitor of appropriate capacitance in the circuit. Explain.

In an $AC$ circuit,$V$ and $I$ are given below. Find the power dissipated in the circuit:
$V = 50 \sin(50t) \ V$
$I = 50 \sin(50t + \frac{\pi}{3}) \ mA$ (in $W$)