An alternating voltage is given by E = 100 si | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given,the alternating voltage is $E = 100 \sin \left(\omega t + \frac{\pi}{6}ight) 	ext{ V}$.For the voltage to be maximum,the sine term must b

Vedclass · Accepted Answer

$\frac{T}{6}$

Vedclass · Answer

(C) Given,the alternating voltage is $E = 100 \sin \left(\omega t + \frac{\pi}{6}ight) 	ext{ V}$.For the voltage to be maximum,the sine term must be equal to $1$.$\sin \left(\omega t + \frac{\pi}{6}ight) = 1$Since $\sin \frac{\pi}{2} = 1$,we have:$\omega t + \frac{\pi}{6} = \frac{\pi}{2}$$\omega t = \frac{\pi}{2} - \frac{\pi}{6} = \frac{3\pi - \pi}{6} = \frac{2\pi}{6} = \frac{\pi}{3}$Using the relation $\omega = \frac{2\pi}{T}$,we substitute $\omega$:$\left(\frac{2\pi}{T}ight) t = \frac{\pi}{3}$$t = \frac{\pi}{3} 	imes \frac{T}{2\pi} = \frac{T}{6}$Thus,the voltage will be maximum for the first time at $t = \frac{T}{6}$.

An alternating voltage is given by $E = 100 \sin \left(\omega t + \frac{\pi}{6}\right) \text{ V}$. The voltage will be maximum for the first time when $t$ is $(T = \text{periodic time})$:

Similar Questions

If $I_1, I_2, I_3$ and $I_4$ are the respective $r.m.s.$ values of the time-varying currents as shown in the four cases $I, II, III$ and $IV$,then identify the correct relation.

If the emf of an $AC$ source is given by $E = 6 \sin \omega t + 4 \sin 2 \omega t \text{ V}$,then the rms value of the emf is

In a circuit,the value of the alternating current is measured by a hot wire ammeter as $10 \ A$. Its peak value will be: (in $A$)

$A$ sinusoidal voltage produced by an $AC$ generator at any instant $t$ is given by the equation $V = 311 \sin(314t)$. The $rms$ value of voltage and frequency are respectively:

The average value of an $A$.$C$. voltage given by $V = V_{m} \sin(\omega t)$ over the time interval $t = 0$ to $t = \frac{\pi}{\omega}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module