An alkene (A) C_{16}H_{16} on ozonolysis give | vedclass

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(B) $1$. Ozonolysis of $C_{16}H_{16}$ gives only one product $C_8H_8O$. This implies $(A)$ is $1,2$-diphenyl$-1-$butene or similar,but specifically,$C

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On catalytic hydrogenation,the 'trans' form of $A$ produces a racemic mixture

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(B) $1$. Ozonolysis of $C_{16}H_{16}$ gives only one product $C_8H_8O$. This implies $(A)$ is $1,2$-diphenyl$-1-$butene or similar,but specifically,$C_8H_8O$ is acetophenone $(PhCOCH_3)$. Thus,$(A)$ is $2,3$-diphenyl$-2-$butene $(Ph(CH_3)C=C(CH_3)Ph)$.$2$. Cyanobenzene $(PhCN)$ + $CH_3MgBr$ followed by hydrolysis gives acetophenone $(PhCOCH_3)$.$3$. $(A)$ is $2,3$-diphenyl$-2-$butene. It shows geometrical isomerism ($cis$ and $trans$).$4$. Option $A$: $2,3$-diphenyl$-2-$butene is planar and achiral,hence optically inactive. This is correct.$5$. Option $B$: Catalytic hydrogenation of $trans-2,3$-diphenyl$-2-$butene yields $meso-2,3$-diphenylbutane,not a racemic mixture. Thus,this statement is incorrect.$6$. Option $C$: Wittig reaction between acetophenone and $Ph_3P=C(CH_3)Ph$ would yield $2,3$-diphenyl$-2-$butene. This is correct.$7$. Option $D$: Syn-dihydroxylation (using peracid followed by hydrolysis) of $trans-alkene$ yields a racemic mixture of the corresponding diol. This is correct.

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