An alcohol X left( C_5 H_{12} O right) produc | vedclass

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(D) $1$. The Lucas test (conc. $HCl / ZnCl_2$) is used to distinguish between primary,secondary,and tertiary alcohols. Tertiary alcohols react instant

Vedclass · Accepted Answer

$3-$methylbutan$-1-$ol,$2$-methylbutan$-2-$ol

Vedclass · Answer

(D) $1$. The Lucas test (conc. $HCl / ZnCl_2$) is used to distinguish between primary,secondary,and tertiary alcohols. Tertiary alcohols react instantly to produce turbidity.$2$. Alcohol $X$ produces turbidity instantly,meaning it must be a tertiary alcohol. Among the isomers of $C_5 H_{12} O$,$2$-methylbutan-$2$-ol is a tertiary alcohol.$3$. Alcohol $Y$ undergoes dehydration with conc. $H_2 SO_4$ at $443 \ K$. This is a characteristic reaction for alcohols to form alkenes.$4$. Comparing the options,$2$-methylbutan-$2$-ol is the tertiary alcohol $(X)$ and $3$-methylbutan-$1$-ol is a primary isomer $(Y)$.$5$. Therefore,the correct pair is $X = 2$-methylbutan-$2$-ol and $Y = 3$-methylbutan-$1$-ol,which corresponds to option $D$.

Group-$I$ (Compound)	Group-$II$ (Use)
$A$. Alcohol	$1$. Antiseptic
$B$. Phenol	$2$. Perfumes
$C$. Ether	$3$. Detergents
$D$. Amine	$4$. Dyes

An alcohol $X \left( C_5 H_{12} O \right)$ produces turbidity instantly with conc. $HCl / ZnCl_2$. Isomer $(Y)$ of $X$ undergoes dehydration with conc. $H_2 SO_4$ at $443 \ K$. $X$ and $Y$ respectively are

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In the following reaction,$\text{Phenol}$ $\xrightarrow{Zn \, \text{dust}} x$ $\xrightarrow[\text{Anhy.} \, ZnCl_2]{CH_3Cl} y$ $\xrightarrow{\text{Alk.} \, KMnO_4} z$. The product $z$ is:

Match the compounds in Group-$I$ with their uses in Group-$II$. Find the correct match for Group-$I$ from Group-$II$.

Group-$I$ (Compound) Group-$II$ (Use)

$A$. Alcohol $1$. Antiseptic

$B$. Phenol $2$. Perfumes

$C$. Ether $3$. Detergents

$D$. Amine $4$. Dyes

Ethanol is prepared industrially by

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