Match the compounds in Group-$I$ with their uses in Group-$II$. Find the correct match for Group-$I$ from Group-$II$.

Group-$I$ (Compound)	Group-$II$ (Use)
$A$. Alcohol	$1$. Antiseptic
$B$. Phenol	$2$. Perfumes
$C$. Ether	$3$. Detergents
$D$. Amine	$4$. Dyes

In the given esterification reaction,the labelled $^{18}O$ will be found in:

Match each of the compounds given in Column $I$ with the reaction$(s)$ that they can undergo,given in Column $II$.
| Column $I$ | Column $II$ |
| :--- | :--- |
| $(A)$ $3-$bromobenzofuran derivative | $(p)$ Nucleophilic substitution |
| $(B)$ Benzyl alcohol | $(q)$ Elimination |
| $(C)$ Salicylaldehyde | $(r)$ Nucleophilic addition |
| $(D)$ $1-$bromo$-2-$nitrobenzene | $(s)$ Esterification with acetic anhydride |
| | $(t)$ Dehydrogenation |

An alcohol $X \left( C_5 H_{12} O \right)$ produces turbidity instantly with conc. $HCl / ZnCl_2$. Isomer $(Y)$ of $X$ undergoes dehydration with conc. $H_2 SO_4$ at $443 \ K$. $X$ and $Y$ respectively are

Match the following column:

Column-$I$ (Reaction)	Column-$II$ (Electrophile)
$A$. $C_6H_6 + CH_3Cl \xrightarrow{AlCl_3} C_6H_5CH_3$	$P$. $CO_2$
$B$. $C_6H_5OH + CO_2 \xrightarrow[H^+]{NaOH} \text{Salicylic acid}$	$Q$. $:CCl_2$
$C$. $C_6H_5OH + CHCl_3 \xrightarrow{KOH} \text{Salicylaldehyde}$	$R$. $\stackrel{+}{C}H_3$
$D$. $C_6H_6 + SO_3 \xrightarrow{H_2SO_4} C_6H_5SO_3H$	$S$. $\stackrel{+}{S}O_3H$
	$T$. $SO_3$

$p-$Cresol reacts with chloroform in an alkaline medium to give compound $A$,which reacts with hydrogen cyanide to form compound $Y$. Hydrolysis of $Y$ gives a chiral carboxylic acid. Identify the structure of the carboxylic acid.