An X-ray tube operates at 30 kV. What is the | vedclass

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(B) The minimum wavelength (cut-off wavelength) of $X$-rays produced in an $X$-ray tube is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Subs

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$0.4$

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(B) The minimum wavelength (cut-off wavelength) of $X$-rays produced in an $X$-ray tube is given by the formula: $\lambda_{\min} = \frac{hc}{eV}$.Substituting the given values:$h = 6.6 	imes 10^{-34} \ J \cdot s$$c = 3 	imes 10^8 \ m/s$$e = 1.6 	imes 10^{-19} \ C$$V = 30 	imes 10^3 \ V$$\lambda_{\min} = \frac{(6.6 	imes 10^{-34}) 	imes (3 	imes 10^8)}{(1.6 	imes 10^{-19}) 	imes (30 	imes 10^3)}$$\lambda_{\min} = \frac{19.8 	imes 10^{-26}}{48 	imes 10^{-16}} = 0.4125 	imes 10^{-10} \ m = 0.4125 \ \mathring{A}$.Rounding to the nearest option,we get $0.4 \ \mathring{A}$.

An $X$-ray tube operates at $30 \ kV$. What is the minimum wavelength emitted in $\mathring{A}$? (Given: $h = 6.6 \times 10^{-34} \ J \cdot s$,$e = 1.6 \times 10^{-19} \ C$,$c = 3 \times 10^8 \ m/s$)

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