The binding energy of the innermost electron | vedclass

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Question

(C) To produce characteristic $X$-rays,the incident electron must have enough energy to knock out an electron from the inner shell of the target atom.

Vedclass · Accepted Answer

$V > 40 	ext{ kV}$

Vedclass · Answer

(C) To produce characteristic $X$-rays,the incident electron must have enough energy to knock out an electron from the inner shell of the target atom.This requires the kinetic energy of the incident electron to be at least equal to the binding energy of the electron in that shell.The kinetic energy of an electron accelerated through a potential difference $V$ is given by $K = eV$.Therefore,to eject an electron from the innermost shell (binding energy $E_b = 40 	ext{ keV}$),the condition is $eV > E_b$.Substituting the values,$eV > 40 	ext{ keV}$,which implies $V > 40 	ext{ kV}$.

The binding energy of the innermost electron in tungsten is $40 \text{ keV}$. To produce characteristic $X$-rays using a tungsten target in an $X$-ray tube,the potential difference $V$ between the cathode and the anti-cathode should be:

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