An $\alpha - $ particle travels in a circular path of radius $0.45\, m$ in a magnetic field $B = 1.2\,Wb/{m^2}$ with a speed of $2.6 \times {10^7}\,m/\sec $. The period of revolution of the $\alpha - $ particle is
An $\alpha - $ particle travels in a circular path of radius $0.45\, m$ in a magnetic field $B = 1.2\,Wb/{m^2}$ with a speed of $2.6 \times {10^7}\,m/\sec $. The period of revolution of the $\alpha - $ particle is
- A
$1.1 \times {10^{ - 5}}\,\sec $
- B
$1.1 \times {10^{ - 6}}\sec $
- C
$1.1 \times {10^{ - 7}}\,\sec $
- D
$1.1 \times {10^{ - 8}}\,\sec $
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