An AND gate is followed by a NOT gate in seri | vedclass

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(B) $1$. An $AND$ gate takes two inputs $A$ and $B$ and produces an output $X = A \cdot B$.$2$. This output $X$ is then passed through a $NOT$ gate.$3

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$\overline{A \cdot B}$

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(B) $1$. An $AND$ gate takes two inputs $A$ and $B$ and produces an output $X = A \cdot B$.$2$. This output $X$ is then passed through a $NOT$ gate.$3$. $A$ $NOT$ gate inverts the input,so the final output $Y = \overline{X}$.$4$. Substituting the value of $X$,we get $Y = \overline{A \cdot B}$.$5$. This combination of an $AND$ gate followed by a $NOT$ gate is known as a $NAND$ gate.

An $AND$ gate is followed by a $NOT$ gate in series. With two inputs '$A$' and '$B$',the Boolean expression for the output '$Y$' will be

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