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(C) The minimum wavelength $(\lambda_{\min})$ of $X$-rays produced by an $X$-ray tube is given by the Duane-Hunt law:$\lambda_{\min} = \frac{hc}{eV} =

Vedclass · Accepted Answer

$27500$

Vedclass · Answer

(C) The minimum wavelength $(\lambda_{\min})$ of $X$-rays produced by an $X$-ray tube is given by the Duane-Hunt law:$\lambda_{\min} = \frac{hc}{eV} = \frac{12400 	ext{ } \mathring{A} \cdot V}{V}$Given $\lambda_{\min} = 0.45 \mathring{A}$.Substituting the value into the formula:$0.45 = \frac{12400}{V}$$V = \frac{12400}{0.45}$$V \approx 27555 	ext{ } V$Comparing this with the given options, the closest value is $27500 	ext{ } V$.

An $X$-ray tube has a short wavelength limit at $0.45 \mathring{A}$. The voltage of the tube is ........ $V$.

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