X-rays of wavelength lambda are reflected fro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When $X$-rays are incident on parallel atomic planes with spacing $d$ at a glancing angle $	heta$,the path difference between the rays reflected

Vedclass · Accepted Answer

$2 d \sin 	heta = n \lambda$

Vedclass · Answer

(D) When $X$-rays are incident on parallel atomic planes with spacing $d$ at a glancing angle $	heta$,the path difference between the rays reflected from successive planes is given by $\Delta x = 2 d \sin 	heta$.For constructive interference (maxima),the path difference must be an integer multiple of the wavelength $\lambda$.Therefore,the condition for maxima is $2 d \sin 	heta = n \lambda$,where $n = 1, 2, 3, \dots$ is the order of the interference fringe. This is known as Bragg's Law.

$X$-rays of wavelength $\lambda$ are reflected from parallel planes of atoms in a crystal with spacing $d$ between two planes,as shown in the figure. If the two reflected beams interfere constructively,then the condition for maxima will be (where $n$ is the order of the interference fringe):

Similar Questions

Penetrating power of $X-$rays depends on

Calculate the wavelength of the $K_{\alpha}$ line for $Z=31$, given $a=5 \times 10^7 \text{ Hz}^{1/2}$ for a characteristic $X$-ray spectrum.

Find the $(a)$ maximum frequency,and $(b)$ minimum wavelength of $X$-rays produced by $30 \; kV$ electrons.

When an $X$-ray tube operates at $60 \ kV$,the observed tube current is $50 \ mA$. Assuming that the total energy of the electrons is converted into heat,the rate of heat production at the anode in $cal/s$ is:

Calculate the wavelength of the $K_{\alpha}$ line for $Z=31$, when $a=5 \times 10^7 \, Hz^{1/2}$ for a characteristic $X$-ray spectrum.

Vedclass Test Series

Exam Paper Generator

Online Exam Module