Among the following molecules / ions C_2^{2-} | vedclass

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Question

$C_2^{2 - } - {\sigma _{1s}}2{\sigma ^*}_{1s}2{\sigma _{2s}}2{\sigma ^*}_{2{s^2}}[{\pi _{2p_x^2}} = {\pi _2}p_y^2]{\sigma _{2p_z^2}}$

$B.O = \frac{

Vedclass · Accepted Answer

$C_2^{2-}$

Vedclass · Answer

$C_2^{2 - } - {\sigma _{1s}}2{\sigma ^*}_{1s}2{\sigma _{2s}}2{\sigma ^*}_{2{s^2}}[{\pi _{2p_x^2}} = {\pi _2}p_y^2]{\sigma _{2p_z^2}}$

$B.O = \frac{{10 - 4}}{2} = 3$ (diamagnetic)

$N_2^{2 - } - {\sigma _{1s}}2{\sigma ^*}_{1s}2{\sigma _{2s}}2{\sigma ^*}_{2{s^2}}[{\pi _{2p_x^2}} = {\pi _2}p_y^2]{\sigma _{2p_z^2}}[{\pi _{2p_x^1}} = {\pi ^*}_{2p_y^1}]$

$B.O = \frac{{10 - 6}}{2} = 2$ (paramagnetic)

$O_2^{2 - } - {\sigma _{1s}}2{\sigma ^*}_{1s}2{\sigma _{2s}}2{\sigma ^*}_{2s}2{\sigma _{2p_z^2}}[{\pi _{2p_x^2}} = {\pi _2}p_y^2]\,[{\pi _{2p_x^2}} = {\pi ^*}_2p_y^2]$

$B.O = \frac{{10 - 8}}{2} = 1$ (diamagnetic)

${O_2} - {\sigma _{1s}}2{\sigma ^*}_{1s}2{\sigma _{2s}}2{\sigma ^*}_{2s}2{\sigma _{2p_z^2}}\,[{\pi _{2p_x^2}} = {\pi _2}p_y^2]\,[{\pi _{2p_x^2}} = {\pi ^*}_2p_y^2]$

$B.O = \frac{{10 - 6}}{2} = 2$ (paramagnetic)

Among the following molecules / ions $C_2^{2-} ,N_2^{2-} ,O_2^{2-},O_2$ which one is diamagnetic and has the shortest bond length ?

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