Among $15$ players, $8$ are batsmen and $7$ are bowlers. Find the probability that a team is chosen of $6$ batsmen and $5$ bowlers
$\frac{{{}^8{C_6} \times {}^7{C_5}}}{{{}^{15}{C_{11}}}}$
$\frac{{^8{C_6}{ + ^7}{C_5}}}{{^{15}{C_{11}}}}$
$\frac{{15}}{{28}}$
None of these
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