Among NH_3, BCl_3, Cl_2 and N_2,the compound | vedclass

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(B) The correct answer is $B$. According to the octet rule,atoms of different elements combine with each other to complete their respective octets (i.

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$BCl_3$

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(B) The correct answer is $B$. According to the octet rule,atoms of different elements combine with each other to complete their respective octets (i.e.,$8$ electrons in their outermost shell,or $2$ electrons in the case of $H, Li,$ and $Be$ to attain a stable nearest noble gas configuration). In $BCl_3$,the central Boron $(B)$ atom has only $6$ electrons in its valence shell after forming three covalent bonds with Chlorine atoms. Since $6 < 8$,$BCl_3$ is an electron-deficient molecule and does not satisfy the octet rule.

Among $NH_3, BCl_3, Cl_2$ and $N_2$,the compound that does not satisfy the octet rule is

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