Among B_2H_6, B_3N_3H_6, N_2O, N_2O_4, H_2S_2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let us analyze the structures of the given molecules to identify those with a covalent bond between two atoms of the same kind:$1$. $B_2H_6$ (Dibo

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) Let us analyze the structures of the given molecules to identify those with a covalent bond between two atoms of the same kind:$1$. $B_2H_6$ (Diborane): Contains $B-H-B$ bridge bonds. There is no $B-B$ bond.$2$. $B_3N_3H_6$ (Borazine): Contains $B-N$ bonds. There is no $B-B$ or $N-N$ bond.$3$. $N_2O$: The structure is $N \equiv N \rightarrow O$. It contains an $N-N$ bond.$4$. $N_2O_4$: The structure is $O_2N-NO_2$. It contains an $N-N$ bond.$5$. $H_2S_2O_3$ (Thiosulfuric acid): The structure contains an $S-S$ bond.$6$. $H_2S_2O_8$ (Peroxodisulfuric acid): The structure contains an $O-O$ (peroxide) bond.Thus,the molecules containing a covalent bond between two atoms of the same kind are $N_2O, N_2O_4, H_2S_2O_3$,and $H_2S_2O_8$.The total number of such molecules is $4$.

Among $B_2H_6, B_3N_3H_6, N_2O, N_2O_4, H_2S_2O_3$ and $H_2S_2O_8$,the total number of molecules containing a covalent bond between two atoms of the same kind is . . . .

Similar Questions

The number of electrons involved in the bond formation of $N_2$ molecule is:

Which of the following bonds requires the highest bond energy to dissociate the bonded atoms?

The total number of electrons that take part in forming bonds in $N_2$ is

The octet rule is not followed in

Draw the Lewis structures for the following molecules and ions:
$H_2S, SiCl_4, BeF_2, CO_3^{2-}, HCOOH$

Vedclass Test Series

Exam Paper Generator

Online Exam Module