Among (i) [Co(NH_3)_6]Cl_3,(ii) [Ni(NH_3)_6]C | vedclass

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(A) $(i) [Co(NH_3)_6]Cl_3$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons. All $6$ electrons are paired,so it is d

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$(i)$

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(A) $(i) [Co(NH_3)_6]Cl_3$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing of electrons. All $6$ electrons are paired,so it is diamagnetic.$(ii) [Ni(NH_3)_6]Cl_2$: $Ni^{2+}$ is $3d^8$. It has $2$ unpaired electrons,so it is paramagnetic.$(iii) [Cr(H_2O)_6]Cl_3$: $Cr^{3+}$ is $3d^3$. It has $3$ unpaired electrons,so it is paramagnetic.$(iv) [Fe(H_2O)_6]Cl_2$: $Fe^{2+}$ is $3d^6$. $H_2O$ is a weak field ligand,so it has $4$ unpaired electrons,making it paramagnetic.

Among $(i) [Co(NH_3)_6]Cl_3$,$(ii) [Ni(NH_3)_6]Cl_2$,$(iii) [Cr(H_2O)_6]Cl_3$,$(iv) [Fe(H_2O)_6]Cl_2$,the complex which is diamagnetic is $....$

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