Aluminium chloride in acidified aqueous solut | vedclass

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(A) $AlCl_{3}$ in an acidified aqueous solution undergoes hydration to form the octahedral complex $[Al(H_{2}O)_{6}]^{3+}$.The electronic configuratio

Vedclass · Accepted Answer

$[Al(H_{2}O)_{6}]^{3+}, sp^{3}d^{2}$

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(A) $AlCl_{3}$ in an acidified aqueous solution undergoes hydration to form the octahedral complex $[Al(H_{2}O)_{6}]^{3+}$.The electronic configuration of $Al^{3+}$ is $[Ne] \ 3s^{0} \ 3p^{0} \ 3d^{0}$.To accommodate six water ligands,the $Al^{3+}$ ion utilizes one $3s$,three $3p$,and two $3d$ orbitals,resulting in $sp^{3}d^{2}$ hybridisation.Therefore,$A = [Al(H_{2}O)_{6}]^{3+}$ and $B = sp^{3}d^{2}$.

Aluminium chloride in acidified aqueous solution forms a complex $A$,in which hybridisation of $Al$ is $B$. What are $A$ and $B$,respectively?

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