The shape of [Cu(NH_3)_4]^{2+} is square plan | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$. For $Cu^{2+}$,the configuration is $[Ar] 3d^9$. In the $[Cu(NH_3)_4]^{2+}$ c

Vedclass · Accepted Answer

$dsp^2$ hybridised

Vedclass · Answer

(B) The electronic configuration of $Cu$ $(Z=29)$ is $[Ar] 3d^{10} 4s^1$. For $Cu^{2+}$,the configuration is $[Ar] 3d^9$. In the $[Cu(NH_3)_4]^{2+}$ complex,the $Cu^{2+}$ ion undergoes $dsp^2$ hybridisation to form a square planar geometry. One of the $3d$ electrons is promoted to the $4p$ orbital to allow for the $dsp^2$ hybridisation,which involves one $3d$,one $4s$,and two $4p$ orbitals.

The shape of $[Cu(NH_3)_4]^{2+}$ is square planar. The $Cu^{2+}$ ion in this complex is:

Similar Questions

The hybridization observed in the $[PtCl_6]^{2-}$ ion is .......

Which of the following has a square planar geometry? $(Co = 27, Ni = 28, Fe = 26, Pt = 78)$

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

The geometry of the cuprammonium ion $[Cu(NH_3)_4]^{2+}$ is:

$NiCl_2\{P(C_2H_5)_2(C_6H_5)\}_2$ exhibits temperature-dependent magnetic behaviour (paramagnetic/diamagnetic). The coordination geometries of $Ni^{2+}$ in the paramagnetic and diamagnetic states are respectively

Vedclass Test Series

Exam Paper Generator

Online Exam Module