Aditya invests Rs. 50,000 in a fixed deposit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: Calculate the amount after $2$ years of compound interest $(C.I.)$.Amount $A = P(1 + R/100)^n$$A = 50000(1 + 10/100)^2 = 50000(1.1)^2 =

Vedclass · Accepted Answer

$82280$

Vedclass · Answer

(C) Step $1$: Calculate the amount after $2$ years of compound interest $(C.I.)$.Amount $A = P(1 + R/100)^n$$A = 50000(1 + 10/100)^2 = 50000(1.1)^2 = 50000 	imes 1.21 = Rs. 60500$.Step $2$: Calculate the simple interest $(S.I.)$ on this amount for $3$ years at $12 \%$ per annum.$S.I. = (P 	imes R 	imes T) / 100$$S.I. = (60500 	imes 12 	imes 3) / 100 = 605 	imes 36 = Rs. 21780$.Step $3$: Calculate the final total amount.Final Amount = Principal for $S.I. + S.I. = 60500 + 21780 = Rs. 82280$.

Aditya invests $Rs. 50,000$ in a fixed deposit at $10 \%$ $C.I.$ for $2$ years. At the end of $2$ years,she puts the money in another deposit at $12 \%$ $S.I.$ for $3$ years. What was the final value (in $Rs.$) of the initial investment?

Similar Questions

Albert invested an amount of ₹ $8000$ in a fixed deposit scheme for $2$ years at a compound interest rate of $5 \%$ per annum. How much amount (in ₹) will Albert get on maturity of the fixed deposit?

If the amount is $6 \frac{1}{4}$ times the principal after $2$ years at compound interest,the rate of interest (in $\%$) per annum is

The difference between the simple and compound interest on a certain sum of money for $2$ years at $4 \%$ per annum is $Rs. 4$. Find the sum (In $Rs.$)?

The compound interest on $₹ 1,800$ at $10 \%$ per annum for a certain period of time is $₹ 378$. Find the time in years.

$A$ sum of money placed at compound interest doubles itself in $4$ $years$. In how many $years$ will it amount to four times itself?

Vedclass Test Series

Exam Paper Generator

Online Exam Module