The adiabatic modulus of elasticity of a gas | vedclass

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Question

(B) The adiabatic modulus of elasticity $(E_{\phi})$ is related to the isothermal modulus of elasticity $(E_{	heta})$ by the adiabatic index $\gamma$

Vedclass · Accepted Answer

$1.5 	imes 10^5 \ N/m^2$

Vedclass · Answer

(B) The adiabatic modulus of elasticity $(E_{\phi})$ is related to the isothermal modulus of elasticity $(E_{	heta})$ by the adiabatic index $\gamma$ as follows:$E_{\phi} = \gamma E_{	heta}$Therefore,the isothermal modulus of elasticity is given by:$E_{	heta} = \frac{E_{\phi}}{\gamma}$Given:$E_{\phi} = 2.1 	imes 10^5 \ N/m^2$$\gamma = \frac{C_p}{C_v} = 1.4$Substituting the values:$E_{	heta} = \frac{2.1 	imes 10^5}{1.4}$$E_{	heta} = 1.5 	imes 10^5 \ N/m^2$Thus,the correct option is $B$.

The adiabatic modulus of elasticity of a gas is $2.1 \times 10^5 \ N/m^2$. What will be its isothermal modulus of elasticity? (Given: $\frac{C_p}{C_v} = 1.4$)

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