Addition of $HBr$ to propene in the presence of a peroxide takes place contrary to Markovnikov rule. This can be explained by the mechanism involving

$R_f$ value for $2$-methylpropene in a solvent system (Ethyl acetate + ether) is $0.42$. $2$-methylpropene is treated with dilute $H_2SO_4$ to give major organic product $(X)$. $R_f$ value for $(X)$ in the same solvent system under identical condition will be:

The major product in the reaction is

In the given reaction,$(x)$ will be:

The name of the product obtained by the addition of $HI$ to propene in the presence of a peroxide catalyst is:

Given below are two statements.
Statement $I :$ The presence of weaker $\pi$-bonds makes alkenes less stable than alkanes.
Statement $II :$ The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements,choose the correct answer from the options given below.