Acidized KMnO_4 solution does not oxidise: | vedclass

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(D) Acidified $KMnO_4$ is a strong oxidizing agent. It can oxidize $C_2O_4^{2-}$ to $CO_2$,$NO_2^{-}$ to $NO_3^{-}$,and $S^{2-}$ to $S$. However,$F^{-

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$F^{-} \ (aq.)$

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(D) Acidified $KMnO_4$ is a strong oxidizing agent. It can oxidize $C_2O_4^{2-}$ to $CO_2$,$NO_2^{-}$ to $NO_3^{-}$,and $S^{2-}$ to $S$. However,$F^{-}$ is the conjugate base of the weakest acid $HF$ and is the weakest reducing agent among the halides. Fluorine $(F_2)$ is the strongest oxidizing agent,meaning $F^{-}$ cannot be oxidized by $KMnO_4$ because its oxidation potential is very low and it is already in its most stable oxidation state $(-1)$.

Acidized $KMnO_4$ solution does not oxidise:

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