Potassium dichromate acts as a strong oxidizi | vedclass

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(B) In acidic solution,potassium dichromate $(K_2Cr_2O_7)$ acts as an oxidizing agent. The reduction half-reaction is given by:$Cr_2O_7^{2-} + 14H^+ +

Vedclass · Accepted Answer

$+6$ to $+3$

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(B) In acidic solution,potassium dichromate $(K_2Cr_2O_7)$ acts as an oxidizing agent. The reduction half-reaction is given by:$Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$In $Cr_2O_7^{2-}$,the oxidation state of $Cr$ is calculated as:$2x + 7(-2) = -2$ $\Rightarrow 2x - 14 = -2$ $\Rightarrow 2x = 12$ $\Rightarrow x = +6$In $Cr^{3+}$,the oxidation state of $Cr$ is $+3$.Thus,the oxidation state of chromium changes from $+6$ to $+3$.

Potassium dichromate acts as a strong oxidizing agent in acidic solution. During this process,the oxidation state of chromium changes from

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