Acid and water are mixed in a vessel $A$ in the ratio of $5:2$ and in the vessel $B$ in the ratio $8:5$. In what proportion should quantities be taken out from the two vessels so as to form a mixture in which the acid and water will be in the ratio of $9:4$?

  • A
    $7:2$
  • B
    $2:7$
  • C
    $7:4$
  • D
    $2:3$

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