Acid D formed in the reaction sequence is: | vedclass

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Question

(B) The reaction sequence is as follows:$1$. $C_2H_5Br$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form ethene $(CH_2=CH_2)$ as product $A$.

Vedclass · Accepted Answer

Succinic acid

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(B) The reaction sequence is as follows:$1$. $C_2H_5Br$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form ethene $(CH_2=CH_2)$ as product $A$.$2$. Ethene $(A)$ reacts with $Br_2$ in $CCl_4$ (electrophilic addition) to form $1,2-$dibromoethane $(BrCH_2-CH_2Br)$ as product $B$.$3$. $1,2-$dibromoethane $(B)$ reacts with excess $KCN$ (nucleophilic substitution) to form succinonitrile $(NC-CH_2-CH_2-CN)$ as product $C$.$4$. Succinonitrile $(C)$ undergoes acid hydrolysis $(H_3O^+)$ to form succinic acid $(HOOC-CH_2-CH_2-COOH)$ as product $D$.

Acid $D$ formed in the reaction sequence is:

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