The compound from which formic acid cannot be | vedclass

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(D) Formic acid $(HCOOH)$ cannot be prepared from methyl magnesium bromide $(CH_{3}MgBr)$ because Grignard reagents react with $CO_{2}$ to form carbox

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methyl magnesium bromide

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(D) Formic acid $(HCOOH)$ cannot be prepared from methyl magnesium bromide $(CH_{3}MgBr)$ because Grignard reagents react with $CO_{2}$ to form carboxylic acids with at least two carbon atoms (e.g.,acetic acid). Formic acid can be prepared from the other reagents as follows: $(a)$ $CH_{3}OH$ $\xrightarrow{[O]} HCHO$ $\xrightarrow{[O]} HCOOH$ $(b)$ $CO + NaOH$ $\longrightarrow HCOONa$ $\xrightarrow{H_{2}SO_{4}} HCOOH + NaHSO_{4}$ $(c)$ Glycerol + Oxalic acid $\xrightarrow{383 \ K} HCOOH + 	ext{glycerol}$

The compound from which formic acid cannot be prepared is

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