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(B) The radius of the circular path of a charged particle in a uniform magnetic field is given by $r = \frac{mv}{qB}$.From the figure,the radius $r$ o

Vedclass · Accepted Answer

$1, 2$ only are correct

Vedclass · Answer

(B) The radius of the circular path of a charged particle in a uniform magnetic field is given by $r = \frac{mv}{qB}$.From the figure,the radius $r$ of the path is decreasing as the particle moves.Statement $[1]$: If the magnetic field strength $B$ increases,the radius $r$ decreases $(r \propto \frac{1}{B})$. Thus,this is a possible explanation.Statement $[2]$: As the particle moves through air,it loses kinetic energy $(K = \frac{1}{2}mv^2)$ due to collisions and ionization of air molecules. Since $r = \frac{\sqrt{2mK}}{qB}$,a decrease in kinetic energy $K$ leads to a decrease in radius $r$. Thus,this is a possible explanation.Statement $[3]$: If the particle loses charge $q$,the radius $r$ would increase $(r \propto \frac{1}{q})$,which contradicts the observed path. Therefore,this statement is incorrect.Thus,statements $[1]$ and $[2]$ are correct.

List-$I$	List-$II$
$a$. Fleming's left-hand rule	$e$. Direction of induced current
$b$. Fleming's right-hand rule	$f$. South pole
$c$. Clockwise current	$g$. North pole
$d$. Anticlockwise current	$h$. Direction of force

Similar Questions

The dimensional formula of $\frac{1}{2} \mu_0 H^2$ (where $\mu_0$ is the permeability of free space and $H$ is the magnetic field intensity) is:

Three infinite wires are arranged in space in three dimensions (along $x$,$y$,and $z$ axes) as shown. Each wire carries current $i$. Find the magnetic field at point $A$ located at $(r, -r, 0)$.

Match the following:
List-$I$ List-$II$
$a$. Fleming's left-hand rule $e$. Direction of induced current
$b$. Fleming's right-hand rule $f$. South pole
$c$. Clockwise current $g$. North pole
$d$. Anticlockwise current $h$. Direction of force

The correct answer is:

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