A steady current is set up in a cubic network composed of wires of equal resistance and length $d$ as shown in figure. What is the magnetic field at the centre P due to the cubic network
A steady current is set up in a cubic network composed of wires of equal resistance and length $d$ as shown in figure. What is the magnetic field at the centre P due to the cubic network
- A
$\frac{\mu_0}{4 \pi} \frac{2 I}{d}$
- B
$\frac{\mu_0}{4 \pi} \frac{2 I}{\sqrt{2} d}$
- C
$0$
- D
$\frac{\mu_0}{4 \pi} \frac{\theta \pi I}{d}$
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A straight wire carrying a current of $14\,A$ is bent into a semicircular are of radius $2.2\,cm$ as shown in the figure. The magnetic field produced by the current at the centre $(O)$ of the arc. is $.........\,\times 10^{-4}\, T$
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$(B)$ $|\vec{B}(x, y)|$ depends on $x$ and $y$ only through the radial distance $r=\sqrt{x^2+y^2}$
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$(D)$ $\vec{B}(x, y)$ points normally outward from the $x y$-plane for all the points between the two loops
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