Acetamide is treated with the following reage | vedclass

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(A) The reaction that converts an amide $(-CONH_2)$ into a primary amine $(-NH_2)$ with one carbon atom less is known as the $Hofmann$ bromamide degra

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$NaOH + Br_2$

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(A) The reaction that converts an amide $(-CONH_2)$ into a primary amine $(-NH_2)$ with one carbon atom less is known as the $Hofmann$ bromamide degradation reaction.Among the given reagents,$NaOH + Br_2$ (alkaline solution of bromine) is the specific reagent used for this transformation.Acetamide $(CH_3CONH_2)$ reacts with $NaOH$ and $Br_2$ to yield methylamine $(CH_3NH_2)$.The chemical equation is: $CH_3CONH_2 + 4NaOH + Br_2 \rightarrow CH_3NH_2 + Na_2CO_3 + 2NaBr + 2H_2O$.

Acetamide is treated with the following reagents separately. Which one of these would yield methylamine?

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