CH_3CONH_2 xrightarrow{Na + ROH} Z + H_2O. Wh | vedclass

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Question

(A) The reaction of an amide $(CH_3CONH_2)$ with sodium $(Na)$ and alcohol $(ROH)$ is a reduction reaction.This is a specific method for the reduction

Vedclass · Accepted Answer

$CH_3CH_2NH_2$

Vedclass · Answer

(A) The reaction of an amide $(CH_3CONH_2)$ with sodium $(Na)$ and alcohol $(ROH)$ is a reduction reaction.This is a specific method for the reduction of amides to primary amines.The reaction proceeds as follows: $CH_3CONH_2 + 4[H] \xrightarrow{Na + ROH} CH_3CH_2NH_2 + H_2O$.Therefore,$Z$ is $CH_3CH_2NH_2$.

$CH_3CONH_2 \xrightarrow{Na + ROH} Z + H_2O$. What is $Z$?

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