Acetaldehyde reacts with semicarbazide,the pr | vedclass

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Question

(A) Acetaldehyde $(CH_3CHO)$ reacts with semicarbazide $(NH_2NHCONH_2)$ to form acetaldehyde semicarbazone $(CH_3CH=NNHCONH_2)$.This is a nucleophilic

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$CH_3CH=NNHCONH_2$

Vedclass · Answer

(A) Acetaldehyde $(CH_3CHO)$ reacts with semicarbazide $(NH_2NHCONH_2)$ to form acetaldehyde semicarbazone $(CH_3CH=NNHCONH_2)$.This is a nucleophilic addition-elimination reaction.The nitrogen atom of the $-NH_2$ group attached to the $-NH-$ group acts as the nucleophile because its lone pair is not involved in resonance with the carbonyl group,unlike the amide nitrogen.$CH_3CHO + NH_2NHCONH_2 \rightarrow CH_3CH=NNHCONH_2 + H_2O$

Acetaldehyde reacts with semicarbazide,the product will be:

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