According to Joule's law,if the potential dif | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The power dissipated as heat in a conductor is given by $P = \frac{V^2}{R}$.We know that the resistance $R$ of a conductor is given by $R = \frac{

Vedclass · Accepted Answer

$\frac{1}{\rho}$

Vedclass · Answer

(D) The power dissipated as heat in a conductor is given by $P = \frac{V^2}{R}$.We know that the resistance $R$ of a conductor is given by $R = \frac{\rho l}{A}$,where $\rho$ is the specific resistance (resistivity),$l$ is the length,and $A$ is the cross-sectional area.Substituting the expression for $R$ into the power formula,we get $P = \frac{V^2}{(\rho l / A)} = \frac{A V^2}{\rho l}$.Given that the potential difference $V$,length $l$,and cross-sectional area $A$ are constant,the term $\frac{A V^2}{l}$ is a constant.Therefore,$P \propto \frac{1}{\rho}$.Thus,the heat produced is directly proportional to $\frac{1}{\rho}$.

According to Joule's law,if the potential difference across a conductor having a material of specific resistance remains constant,then the heat produced in the conductor is directly proportional to

Similar Questions

What is the maximum voltage that can be safely applied across a resistor of $196 \,\Omega - 1 \,W$ rating? .......... $volt$

The resistance of a bulb filament changes with temperature. If a bulb rated at $220 \ V$ and $100 \ W$ is connected to a supply of $(220 \times 0.8) \ V$,the actual power consumed will be:

How much work is required to carry a $6 \mu C$ charge from the negative terminal to the positive terminal of a $9 V$ battery?

An electric heater consists of a nichrome coil and runs under $220 \,V$,consuming $1 \,kW$ power. Part of its coil burned out and it was reconnected after cutting off the burnt portion. The power it will consume now is

Which device can convert all electrical energy into heat?

Vedclass Test Series

Exam Paper Generator

Online Exam Module