According to Bohr's theory,the electron in or | vedclass

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(D) According to the Heisenberg uncertainty principle,the relationship between energy uncertainty $\Delta E$ and time uncertainty $\Delta t$ is given

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Infinite

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(D) According to the Heisenberg uncertainty principle,the relationship between energy uncertainty $\Delta E$ and time uncertainty $\Delta t$ is given by $\Delta E \cdot \Delta t \geq \frac{h}{4\pi}$.In Bohr's theory,the energy levels of an electron in an orbit are considered to be perfectly definite,meaning the uncertainty in energy $\Delta E = 0$.Substituting $\Delta E = 0$ into the uncertainty relation: $0 \cdot \Delta t \geq \frac{h}{4\pi}$,which implies $\Delta t \rightarrow \infty$.Therefore,the lifetime of an excited state in the context of Bohr's model is infinite.

According to Bohr's theory,the electron in orbits has definite energy values. Then,according to the uncertainty principle,the lifetime of an excited state will be:

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