(C) For the block,the forces are balanced as follows:$T \cos 37^{\circ} = f$$N + T \sin 37^{\circ} = Mg$Since $f = \mu N$,we have $T \cos 37^{\circ} =

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(C) For the block,the forces are balanced as follows:$T \cos 37^{\circ} = f$$N + T \sin 37^{\circ} = Mg$Since $f = \mu N$,we have $T \cos 37^{\circ} = \mu (Mg - T \sin 37^{\circ})$.Substituting the values $M = 100 \, kg$,$\mu = 1/3$,$\cos 37^{\circ} = 4/5$,and $\sin 37^{\circ} = 3/5$:$T(4/5) = (1/3)(100g - T(3/5))$$12T/5 = 100g - 3T/5$$15T/5 = 100g \implies 3T = 100g \implies T = 100g/3$.For the person,the upward force is $T = 100g/3$ and the downward force is $mg = 25g$.The equation of motion is $T - mg = ma_{\max}$.$100g/3 - 25g = 25a_{\max}$$(100g - 75g)/3 = 25a_{\max}$$25g/3 = 25a_{\max}$$a_{\max} = g/3$.

Class 11 Physics Newton's Laws of Motion and Friction Mix Examples-Newton's Laws of Motion and Friction

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$A$ block of mass $M = 100 \, kg$ is pulled by a force $T$ at an angle of $37^{\circ}$ with the horizontal. The coefficient of friction between the block and the ground is $\mu = 1/3$. $A$ person of mass $m = 25 \, kg$ is standing on a platform and pulls the block with the force $T$. Find the maximum upward acceleration $a_{\max}$ of the person such that the block just starts to move.

A
$\frac{4g}{3}$
B
$\frac{g}{2}$
C
$\frac{g}{3}$
D
$\frac{3g}{4}$

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Newton's Laws of Motion and Friction

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Mix Examples-Newton's Laws of Motion and Friction

Two identical balls are connected by a massless and inextensible thread of length $L$. The system is in gravity-free space with the thread just taut. At $t = 0$,each ball is imparted a velocity $v$; one ball is given a velocity towards the other ball,and the other is given a velocity perpendicular to the first. Then,

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$A$ force of $mg$ is applied to block $B$ to keep the system in equilibrium. Find the value of $T_1$.

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In the following problem,indicate the correct direction of the friction force acting on the cylinder,which is pulled on a rough surface by a constant force $F$. $A$ spool is pulled horizontally by a constant force $F$ applied below the center of mass. Which of the following diagrams correctly shows the direction of the friction force?

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$A$ block of mass $m$ is lying on a rough inclined plane having an inclination $\alpha = \tan^{-1}(\frac{1}{5})$. The inclined plane is moving horizontally with a constant acceleration of $a = 2 \text{ ms}^{-2}$ as shown in the figure. The minimum value of the coefficient of friction,so that the block remains stationary with respect to the inclined plane,is (Take $g = 10 \text{ ms}^{-2}$):

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Which of the following is not a fundamental force in nature?

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$A$ force of $mg$ is applied to block $B$ to keep the system in equilibrium. Find the value of $T_1$.

Which of the following is not a fundamental force in nature?

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