$A$ wire of length $5 \,m$ is twisted through $30^{\circ}$ at its free end. If the radius of the wire is $1 \,mm$,the shearing strain in the wire is: (in $^{\circ}$)

  • A
    $30$
  • B
    $0.18$
  • C
    $1$
  • D
    $0.36$

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