A wire can sustain a weight of 15 , kg. If it | vedclass

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(C) The breaking force or the maximum weight a wire can sustain is determined by its breaking stress.Breaking stress is a material property and does n

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$15$

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(C) The breaking force or the maximum weight a wire can sustain is determined by its breaking stress.Breaking stress is a material property and does not depend on the length of the wire.Breaking Stress $= \frac{	ext{Breaking Force}}{	ext{Area of Cross-section}} = \frac{F}{A}$.Since the material and the cross-sectional area $(A)$ of the wire remain the same when it is cut into smaller pieces,the breaking stress remains constant.Therefore,the maximum weight that each part can sustain remains the same as the original wire.Thus,each part can sustain a weight of $15 \, kg$.

Column-$I$	Column-$II$
$(a)$ $\text{Stress} \propto \text{Strain}$	$(i)$ $M^1 L^{-1} T^{-2}$
$(b)$ $\text{Dimensional formula for compressibility}$	$(ii)$ $M^{-1} L^1 T^2$
	$(iii)$ $\text{Poisson's ratio}$
	$(iv)$ $\text{Hooke's law}$

$A$ wire can sustain a weight of $15 \, kg$. If it is cut into four equal parts,then each part can sustain a weight of ........ $kg$.

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