Class 11PhysicsMechanical Properties of SolidsBasic of Elasticity, Stress and Strain relationship and Graphical analysis
EasyDimensions of strain are
- A$MLT^{-1}$
- B$ML^2T^{-1}$
- C$MLT^{-2}$
- D$M^0L^0T^0$
Explore More
Similar Questions
The length of a metal wire is $l_1$ when the tension in it is $F_1$ and $l_2$ when the tension is $F_2$. Then,the original length of the wire is
Match the physical quantities in Column-$I$ with the details given in Column-$II$ appropriately:
Column-$I$ Column-$II$ $(a)$ $\text{Stress} \propto \text{Strain}$ $(i)$ $M^1 L^{-1} T^{-2}$ $(b)$ $\text{Dimensional formula for compressibility}$ $(ii)$ $M^{-1} L^1 T^2$ $(iii)$ $\text{Poisson's ratio}$ $(iv)$ $\text{Hooke's law}$
| Column-$I$ | Column-$II$ |
|---|---|
| $(a)$ $\text{Stress} \propto \text{Strain}$ | $(i)$ $M^1 L^{-1} T^{-2}$ |
| $(b)$ $\text{Dimensional formula for compressibility}$ | $(ii)$ $M^{-1} L^1 T^2$ |
| $(iii)$ $\text{Poisson's ratio}$ | |
| $(iv)$ $\text{Hooke's law}$ |
Easy
View Solution$A$ rod of length $2 \ m$ rests on a smooth horizontal floor. If the rod is heated from $0^\circ C$ to $20^\circ C$,find the longitudinal strain developed? $(\alpha = 5 \times 10^{-5} / ^\circ C)$
Medium
View SolutionThe breaking stress for a wire of radius $r$ of a given material is $F \ Nm^{-2}$. The breaking stress for a wire of the same material of radius $2r$ will be:
Medium
View Solution$A$ force of $10 \,N$ is required to break a wire of radius $1 \,mm$. The force required to break the wire of the same material, but radius $3 \,mm$ will be
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo